How do you use Heron's formula to determine the area of a triangle with sides of that are 25, 29, and 32 units in length?

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Answer 1 · 2016-01-11T06:22:28

$A="345 square units"$

Heron's formula is $A=sqrt((s)(s-a)(s-b)(s-c))$ , where $A$ is the area, $s$ is the semiperimeter, and $a, b, and c$ are the sides of the triangle.

Let side $a=25$ .
Let side $b=29$ .
Let side $c=32$ .

Semiperimeter
The formula for the semiperimeter is $s=(a+b+c)/2$ .

$s=(25+29+32)/2$

$s=86/2$

$s=43$

Heron's Formula

$A=sqrt(s(s-a)(s-b)(s-c))$

$A=sqrt(43(43-25)(43-29)(43-32)$

$A=sqrt(119196)$

$A="345 square units"$