Question

How do you use Heron's formula to determine the area of a triangle with sides of that are 15, 18, and 19 units in length?

Answer 1

Area `=126.554" "`square units

Explanation:

Let the sides be `a=15` and `b=18` and `c=19`

Solve for the half perimeter `s=(a+b+c)/2=(15+18+19)/2=26`

The Heron's Formula for the area of the triangle

Area `=sqrt(s(s-a)(s-b)(s-c))`

Area `=sqrt(26(26-15)(26-18)(26-19))`

Area `=126.554" "`square units

God bless....I hope the explanation is useful.

Answer 2

≈ 126.55 square units

Explanation:

This is a 2 step process.

step 1 : Calculate half the perimeter (s) of the triangle.

let a = 15 , b = 18 and c = 19

`s = (a+b+c)/2 = (15+18+19)/2 = 52/2 = 26`

step 2 : Calculate the area using

area `= sqrt(s(s-a)(s-b)(s-c))`

`= sqrt(26(26-15)(26-18)(26-19))`

`= sqrt(26xx11xx8xx7) ≈ 126.55" square units "`