# How do you use the distributive property to factor 5c^2v-15c^2v^2+5c^2v^3?

Jul 26, 2017

See a solution process below:

#### Explanation:

We can rewrite the expression as:

$\left(5 {c}^{2} v \cdot 1\right) - \left(5 {c}^{2} v \cdot 3 v\right) + \left(5 {c}^{2} v \cdot {v}^{2}\right)$

Now, we can factor out the common term:

$5 {c}^{2} v \left(1 - 3 v + {v}^{2}\right) \implies$

$5 {c}^{2} v \left({v}^{2} - 3 v + 1\right)$