Question

How do you use the distributive property to factor `5c^2v-15c^2v^2+5c^2v^3`?

Answer 1

See a solution process below:

Explanation:

We can rewrite the expression as:

`(5c^2v * 1) - (5c^2v * 3v) + (5c^2v * v^2)`

Now, we can factor out the common term:

`5c^2v(1 - 3v + v^2) =>`

`5c^2v(v^2 - 3v + 1)`