How do you use the formula #A=1/2bh# to write a simplified expression for the area of a right triangle with leg lengths of #4xy^-1# and #7x^2#?

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Answer 1 · 2018-05-14T16:41:03

The desired expression is #(14x^3)/y#

We are given that area of a right triangle is #1/2bh#, where #b# and #h# are legs of the triangle.

In the given case legs are #4xy^(-1)# and #7x^2#

hence are of right triangle is #1/2xx4xy^(-1)xx7x^2#

= #14x/yxx x^2#

= #(14x^3)/y#

Answer 2 · 2018-05-14T16:44:15

#A=(14x^3)/y#

#"Area of a triangle"=1/2 base xx height"#

If the base#=4xy^-1#

and the height#= 7x^2#

Then #A=1/2xx4xy^-1xx7x^2#

#:.A=14x^3y^-1#

#:.A=(14x^3)/y#