# How do you use the formula A=1/2bh to write a simplified expression for the area of a right triangle with leg lengths of 4xy^-1 and 7x^2?

May 14, 2018

The desired expression is $\frac{14 {x}^{3}}{y}$

#### Explanation:

We are given that area of a right triangle is $\frac{1}{2} b h$, where $b$ and $h$ are legs of the triangle.

In the given case legs are $4 x {y}^{- 1}$ and $7 {x}^{2}$

hence are of right triangle is $\frac{1}{2} \times 4 x {y}^{- 1} \times 7 {x}^{2}$

= $14 \frac{x}{y} \times {x}^{2}$

= $\frac{14 {x}^{3}}{y}$

May 14, 2018

$A = \frac{14 {x}^{3}}{y}$

#### Explanation:

$\text{Area of a triangle"=1/2 base xx height}$

If the base$= 4 x {y}^{-} 1$

and the height$= 7 {x}^{2}$

Then $A = \frac{1}{2} \times 4 x {y}^{-} 1 \times 7 {x}^{2}$

$\therefore A = 14 {x}^{3} {y}^{-} 1$

$\therefore A = \frac{14 {x}^{3}}{y}$