# How do you use the intercepts to graph -x+4y=8?

You only need two points to draw a line graph,therefore, compute the intercepts $\left(- 8 , 0\right)$ and $\left(0 , 2\right)$ then connect the two points.

#### Explanation:

From the given equation $- x + 4 y = 8$, just set one variable to zero at a time then solve for the numerical value of the other.

Let us do it

$- x + 4 y = 8$

Set $y = 0 \text{ }$and then substitute that value in the equation

$- x + 4 \left(0\right) = 8$

$- x + 0 = 8$

$- x = 8$

$\frac{- x}{- 1} = \frac{8}{- 1}$

and

$x = - 8$
this means there is a point on the line at $\left(- 8 , 0\right)$

Now set $x = 0$ and then substitute that value in the equation

$- \left(0\right) + 4 y = 8$

$0 + 4 y = 8$

$4 y = 8$

$\frac{4 y}{4} = \frac{8}{4}$

$y = 2$

this means there is another point on the line at $\left(0 , 2\right)$

Now, to graph the $- x + 4 y = 8$, you only need to draw a line from $\left(- 8 , 0\right)$ to $\left(0 , 2\right)$

Kindly see the graph of $- x + 4 y = 8$ and check the two points we calculated.

graph{-x+4y=8[-20,20,-10,10]}

God bless...I hope the explanation is useful.