Question

How do you use the law of cosines or law of sines if you are given a = 2, c = 2 and Beta = 10 degrees?

Answer 1

Solve triangle knowing B = 10 deg, a = 2, and c = 2

Explanation:

The triangle is a isosceles triangle. Find A = C and side b.

Use trig identity: `b^2 = a^2 + c^2 - 2ac.cos B`

b^2 = 4 + 4 - 8(0.98) = 0.16 -> b = 0.40

Angle `A = C = (180 - 10)/2 = 85` deg