Question

How do you use the quadratic formula to solve `x^2+6x+10=0`?

Answer 1

Solution: `x= -3+1i and x= -3-1i`

Explanation:

`x^2+6x+10=0`

Comparing with standard quadratic equation `ax^2+bx+c=0`

`a=1 ,b=6 ,c=10` Discriminant `D= b^2-4ac` or

`D=36-40 =-4` If discriminant positive, we get two real

solutions, if it is zero we get just one solution, and if it is negative

we get complex solutions. Discriminant is negative , so it has

complex roots. .Quadratic formula: `x= (-b+-sqrtD)/(2a)`or

`x= (-6+-sqrt(-4))/(-2) = -3+- i [i^2=-1]`

So roots are `x= -3+1i and x= -3-1i` [Ans]