# How do you write 1/2+5i  in polar form and find ?

$z = 5.025 \cdot \left(\cos 1.47 + i \sin 1.47\right)$ Angle expressed in radians.
In polar form $\left(\frac{1}{2} + 5 \cdot i\right)$ lies on the 1st quardrant. The length of it from the origin is $r = \sqrt{{.5}^{2} + {5}^{2}} = \sqrt{25.25} = 5.025$ The argument is $\theta = {\tan}^{-} 1 \left(\frac{5}{.5}\right) \mathmr{and} \theta = {\tan}^{-} 1 10 = 1.47 r a \mathrm{di} a n$
So in Polar form $z = 5.025 \cdot \left(\cos 1.47 + i \sin 1.47\right)$ ; If $\theta$ is expressed in degree then $z = 5.025 \cdot \left(\cos 84.29 + i \sin 84.29\right)$