# How do you write 9.002 times 10^-5  in standard notation?

##### 2 Answers
Aug 6, 2016

In standard notation $9.002 \times {10}^{- 5} = 0.00009002$

#### Explanation:

In scientific notation, we write a number so that it has single digit to the left of decimal sign and is multiplied by an integer power of $10$.

In other words, in scientific notation, a number is written as $a \times {10}^{n}$, where $1 \le a < 10$ and $n$ is an integer and $1 \le a < 10$.

To write the number in normal or standard notation one just needs to multiply by the power ${10}^{n}$ (or divide if $n$ is negative). This means moving decimal $n$ digits to right if multiplying by ${10}^{n}$ and moving decimal $n$ digits to left if dividing by ${10}^{n}$ (i.e. multiplying by ${10}^{- n}$).

In the given case, as we have the number as $9.002 \times {10}^{- 5}$, we need to move decimal digit to the left by five points. For this, let us write $9.002$ as $000009.002$ and moving decimal point five points to left means $0.00009002$

Hence in standard notation $9.002 \times {10}^{- 5} = 0.00009002$

Jan 22, 2017

$0.00009002$

#### Explanation:

$9.002 \times {10}^{-} 5$

$= 9 \frac{2}{1000} \times \frac{1}{100000}$

$= \frac{9002}{1000} \times \frac{1}{100000}$

$= \frac{9002.0}{100000000}$

shift the decimal point 8 places to the left.

$= 0.00009002$