Question

How do you write a quadratic function in intercept form who has x intercepts =16/3, -5/2 and passes through points (-9/2, -25/18)?

Answer 1

`y=-25/354(x-16/3)(x+5/2)`

Explanation:

`"since the roots are "x=16/3" and "x=-5/2`

`rArr(x-16/3)" and "(x+5/2)" are factors"`

`rArry=a(x-16/3)(x+5/2)larrcolor(red)" is the function"`

`"to find a substitute "(-9/2,-25/18)" into the function"`

`rArra(-9/2-16/3)(-9/2+5/2)=-25/18`

`rArra(-59/6)(-2)=-25/18`

`rArr59/3a=-25/18`

`rArra=-25/18xx3/59=-25/354`

`rArry=-25/354(x-16/3)(x+5/2)`
graph{-25/354(x-16/3)(x+5/2) [-10, 10, -5, 5]}