How do you write a quadratic function in intercept form who has x intercepts =16/3, -5/2 and passes through points (-9/2, -25/18)?

1 Answer
Jul 30, 2017

#y=-25/354(x-16/3)(x+5/2)#

Explanation:

#"since the roots are "x=16/3" and "x=-5/2#

#rArr(x-16/3)" and "(x+5/2)" are factors"#

#rArry=a(x-16/3)(x+5/2)larrcolor(red)" is the function"#

#"to find a substitute "(-9/2,-25/18)" into the function"#

#rArra(-9/2-16/3)(-9/2+5/2)=-25/18#

#rArra(-59/6)(-2)=-25/18#

#rArr59/3a=-25/18#

#rArra=-25/18xx3/59=-25/354#

#rArry=-25/354(x-16/3)(x+5/2)#
graph{-25/354(x-16/3)(x+5/2) [-10, 10, -5, 5]}