How do you write a quadratic function in intercept form who has x intercepts -2/3, 1/6 and passes through points (7/3, 13/2)?
1 Answer
Jun 25, 2017
Explanation:
#x=-2/3 " is a root"#
#rArr3x=-2rArr3x+2larr" is a factor"#
#x=1/6" is a root"#
#rArr6x=1rArr6x-1larr" is a factor"#
#rArry=a(3x+2)(6x-1)larrcolor(red)" in intercept form"#
#"to find a substitute " (7/3,13/2)" into the equation"#
#13/2=a(9)(13)=117a#
#rArra=1/18#
#rArry=1/18(3x+2)(6x-1)" is the equation"#
