How do you write a quadratic function whose graph has the given characteristics: vertex: (-3,2), point (3,12)?

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Answer 1 · 2016-11-20T15:01:40

Recall that vertex form is #y = a(x- p)^2 + q#. The vertex is given by #(p, q)# and a point that the function passes through is #(x, y)#.

#12 = a(3 - (-3))^2 + 2#

#12 = a(36) + 2#

#10= 36a#

#a = 5/18#

Hence, the equation is #y = 5/18(x + 3)^2 + 2#

Hopefully this helps!