How do you write an equation given point (-2,3) slope -1?

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Answer 1 · 2016-11-12T03:53:29

#y = -1x + 1#

We can use the point-slope form of the equation to plug in values and solve for the equation.

use the slope of #-1# and the point of #(-2,3)#

#m=-1#
#x_1 = -2#
#y_1 = 3#

The point-slope formula equation is

#y - y_1 = m(x - x_1)#

plug in the values

#y - 3 = -1(x - (-2))# simplify the signs

#y - 3 = -1(x + 2)# distribute the #-1#

#y - 3 = -1x - 2# use additive inverse to isolate the #y#

#y cancel(- 3) cancel(+ 3)= -1x - 2 + 3# simplify

#y = -1x + 1#

Answer 2 · 2016-11-12T03:55:16

Point-slope form: #y-3=-(x+2)#

Y-intercept form: #y=-x+1#

Use the point-slope equation: #y-y_1=m(x-x_1)#, where #(x_1,y_1)# is the given point #(-2,3)#, and #m# is the slope #-1#.

Plug the numbers into the equation.

#y-3=-1(x-(-2))#

Simplify.

#y-3=-(x+2)#

Solve for #y# to get the slope-intercept form #y=mx+b#, where #m# is the slope and #b# is the y-intercept.

Add #3# to both sides.

#y=-x-2+3#

Simplify.

#y=-x+1#,

where #m=-1# and #b=1#.

graph{y=-x+1 [-10, 10, -5, 5]}