How do you write an equation in point slope and slope intercept form given point (8,0), m=1/3?

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Answer 1 · 2017-02-04T12:41:47

Point-slope form: #(y - color(red)(0)) = color(blue)(1/3)(x - color(red)(8))#

Slope-intercept form: #y = color(red)(1/3)x - color(blue)(8/3)#

The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #color(red)(((x_1, y_1)))# is a point the line passes through.

Substituting the point and slope from the problem gives:

#(y - color(red)(0)) = color(blue)(1/3)(x - color(red)(8))#

The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

We can solve the point-slope form of the equation for #y# to obtain the slope-intercept form:

#y - color(red)(0) = (color(blue)(1/3) xx x) - (color(blue)(1/3) xx color(red)(8))#

#y = 1/3x - 8/3#