# How do you write an equation in slope-intercept form for a line with (5,0) and has a slope of -2/3?

Find the y-intercept with the given slope and given point, to find the general equation of $y = \left(- \frac{2}{3}\right) x + \frac{10}{3}$

#### Explanation:

Slope -intercept form is expressed in the form:

$y = m x + b$ where $m$ is the slope and $b$ is the y intercept.

We're given the slope as $- \frac{2}{3}$.

To find $b$, let's fill in the equation with what we know: the slope and a point (an $x$ and associated $y$ point#):

$0 = \left(- \frac{2}{3}\right) 5 + b$ (multiply the fraction by 5, then add it to both sides)

$b = \frac{10}{3}$

That give's the final answer as:

$y = \left(- \frac{2}{3}\right) x + \frac{10}{3}$