# How do you write an equation in slope intercept form of a line containing the coordinates (-3,-6) with a slope of -4?

Apr 10, 2016

$y = - 4 x - 18$

#### Explanation:

Point slope form of equation of a line with slope $m$ and passing through $\left({x}_{1} , {y}_{1}\right)$ is

$\left(y - {y}_{1}\right) = m \times \left(x - {x}_{1}\right)$

In slope intercept form, equation is of the form $y = m x + c$

Thus, equation of a line passing through $\left(- 3 , - 6\right)$ and slope $- 4$ will be

$\left(y - \left(- 6\right)\right) = \left(- 4\right) \times \left(x - \left(- 3\right)\right)$

or $\left(y + 6\right) = \left(- 4\right) \times \left(x + 3\right)$

or $y + 6 = = - 4 x - 12$

In slope intercept form, it would be $y = - 4 x - 18$