How do you write an equation in slope intercept form of a line containing the coordinates (-3,-6) with a slope of -4?

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Answer 1 · 2016-04-10T15:24:35

#y=-4x-18#

Point slope form of equation of a line with slope #m# and passing through #(x_1,y_1)# is

#(y-y_1)=mxx(x-x_1)#

In slope intercept form, equation is of the form #y=mx+c#

Thus, equation of a line passing through #(-3,-6)# and slope #-4# will be

#(y-(-6))=(-4)xx(x-(-3))#

or #(y+6)=(-4)xx(x+3)#

or #y+6==-4x-12#

In slope intercept form, it would be #y=-4x-18#