How do you write an equation of a line given (-1, 3) with slope m=2/3?

1 Answer
smendyka
Dec 17, 2016

#y - 3 = 2/3(x + 1)# or #y = 2/3x + 11/3#

Explanation:

To complete this problem we use the point-slope formula.

The point-slope formula states: #color(red)((y - y_1) = m(x - x_1))#
Where #color(red)(m)# is the slope and #color(red)((x_1, y_1))# is a point the line passes through.

Substituting the information given in the problem produces the equation:

#y - 3 = 2/3(x - -1)#

#y - 3 = 2/3(x + 1)#

Converting this to the more familiar slope-intercept form would give us:

#y - 3 = 2/3x + 2/3#

#y - 3 + 3 = 2/3x + 2/3 + 3#

#y - 0 = 2/3x + 2/3 + 9/3#

#y = 2/3x + 11/3#

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