How do you write an equation of a line given (9,3) and m=-2/3?

1 Answer
Jan 16, 2017

Use the point-slope formula. See below:

Explanation:

The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #color(red)(((x_1, y_1)))# is a point the line passes through.

Substituting the point and slope from the problem gives the equation:

#(y - color(red)(3)) = color(blue)(-2/3)(x - color(red)(9))#

We can also convert to the more familiar slope-intercept form if we solve for #y#.

The slope-intercept form of a linear equation is:

#y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b# is the y-intercept value.

#y - color(red)(3) = (color(blue)(-2/3) xx x) - (color(blue)(-2/3) xx color(red)(9))#

#y - color(red)(3) = -2/3x - (-6)#

#y - color(red)(3) = -2/3x + 6#

#y - color(red)(3) + 3 = -2/3x + 6 + 3#

#y - 0 = -2/3x + 9#

#y = -2/3x + 9#