How do you write an equation of a line given point (3,3) and m=4/3?

1 Answer
Apr 30, 2017

See the solution process below:

Explanation:

The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #color(red)(((x_1, y_1)))# is a point the line passes through.

Substituting the slope and values from the points in the problem gives:

#(y - color(red)(3)) = color(blue)(4/3)(x - color(red)(3))#

We can solve for #y# to transform the equation to the slope-intercept form.The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

#y - color(red)(3) = (color(blue)(4/3) * x) - (color(blue)(4/3) * color(red)(3))#

#y - color(red)(3) = 4/3x - 4#

#y - color(red)(3) + 3 = 4/3x - 4 + 3#

#y - 0 = 4/3x - 1#

#y = color(red)(4/3)x - color(blue)(1)#