# How do you write an equation of a line given point (-4,6) and m=8?

Sep 1, 2016

The equation for the given condition is:
$y$ $-$ $8 x$ $=$ $38$

#### Explanation:

The general equation of a line is given by:
$y$ $=$ $m \cdot x$ $+$ $c$ ;or
This is when you have the $S l o p e$ $\left(m\right)$ and the $I n t e r c e p t$ $\left(c\right)$ given.

If you have a point $\left(X , Y\right)$ as in this case and the $s l o p e$ $\left(m\right)$, the general form is:
$\left(y - Y\right)$ = $m$ $\cdot$ $\left(x - X\right)$

So, for point $\left(- 4 , 6\right)$ and slope $m$ $=$ $8$, this gives
$\left(y - 6\right)$ $=$ $8$ $\cdot$ $\left(x - \left(- 4\right)\right)$ ;or

$\left(y - 6\right)$ $=$ $8$ $\cdot$ $\left(x + 4\right)$ ;or

$\left(y - 6\right)$ $=$ $8 x$ + $32$ ;or

$y$ $-$ $8 x$ $=$ $38$