# How do you write an equation of a line parallel to y= 3/2x-6 and passes through (-6,2)?

Jul 6, 2016

$y = \frac{3}{2} x + 11$

#### Explanation:

The slope of this line is $\frac{3}{2}$; any line parallel to this one has the same slope.
You can use the following general equation and substitute the coordinates of the point (-6,2) in $\left({x}_{0} , {y}_{0}\right)$:

$y - {y}_{0} = m \left(x - {x}_{0}\right)$

so that the requested equation is:

$y - 2 = \frac{3}{2} \left(x + 6\right)$

$y = \frac{3}{2} x + 9 + 2$

$y = \frac{3}{2} x + 11$