# How do you write an equation of a line with points (-1,3), (0,8)?

##### 2 Answers

See a solution process below:

#### Explanation:

First, we need to determine the slope of the line. The formula for find the slope of a line is:

Where

Substituting the values from the points in the problem gives:

Now, we can use the point-slope formula to write and equation for the line. The point-slope form of a linear equation is:

Where

Substituting the slope we calculated above and the values from the first point in the problem gives:

We can also substitute the slope we calculated above and the values from the second point in the problem giving:

We can also convert this equation to slope-intercept form:

#### Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"to calculate m use the "color(blue)"gradient formula"#

#•color(white)(x)m=(y_2-y_1)/(x_2-x_1)#

#"let "(x_1,y_1)=(-1,3)" and "(x_2,y_2)=(0,8)#

#m=(8-3)/(0-(-1))=5/1=5#

#"note that "b=8" since point "(0,8)#

#y=5x+8larrcolor(red)"is equation of line"#