How do you write an equation of the line in point slope form that passes through the given point: (8,-8) ; slope; 3?

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Answer 1 · 2016-05-18T15:54:35

The slope-intercept form of the equation of the line is
#y = 3x#

The slope-intercept equation of a line is #y=mx+b# where
#m=# slope and #b=# the y-intecept

For this equation we are given the slope of #m=3# and the point (8,-8)

The point slope formula would be written as
#y - y_1 = m( x - x_1)#

#m = 3#
#x_1 = 8#
#y_1=-8#

#y - (-8) = 3 (x -8)#

#y + 8 = 3x -24#

#y cancel(+8) cancel(-8) = 3x - 8 + 8 #

#y = 3x + 0#

The slope-intercept form of the equation of the line is
#y = 3x#