How do you write an equation of the line with a slope of # 3/2# and the #y#-intercept #–2?#

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Answer 1 · 2017-07-13T16:17:39

See a solution process below:

The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

Substituting the slope and y-intercept from the problem gives:

#y = color(red)(3/2)x + color(blue)(-2)#

#y = color(red)(3/2)x - color(blue)(2)#