How do you write $d^2-12d+32$ in factored form?

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Answer 1 · 2015-09-20T16:39:25

$color(blue)((d-4)(d-8)$ is the factorised form of the expression.

$d^2−12d+32$

We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like $ad^2 + bd + c$ , we need to think of 2 numbers such that:

$N_1*N_2 = a*c = 1* 32 = 32$

AND

$N_1 +N_2 = b = -12$

After trying out a few numbers we get $N_1 = -8$ and $N_2 =-4$

$(-8)*(-4) = 32$ and $(-8)+ (- 4)= -12$

$d^2−12d+32 = d^2−8d -4d+32$

$=d(d-8) -4(d-8)$

$color(blue)((d-4)(d-8)$ is the factorised form of the expression.

How do you write d^2-12d+32d^2-12d+32 in factored form?