# How do you write f(x) = x^2 + 10x + 24 in vertex form?

The vertex form is $a \cdot {\left(x + h\right)}^{2} + k$ hence for $f \left(x\right)$ we have that
$f \left(x\right) = \left({x}^{2} + 10 x + 25\right) - 1$
$f \left(x\right) = {\left(x + 5\right)}^{2} - 1$