# How do you write  f(x) = x^2 - 3x + 1 in vertex form?

In vertex form $f \left(x\right) = {\left(x - \frac{3}{2}\right)}^{2} - \frac{5}{4}$ Vertex is $\left(\frac{3}{2} , - \frac{5}{4}\right)$
$f \left(x\right) = {x}^{2} - 3 x + 1 = \left({x}^{2} - 3 x + \frac{9}{4}\right) - \frac{9}{4} + 1 = {\left(x - \frac{3}{2}\right)}^{2} - \frac{5}{4}$ Vertex =$\left(\frac{3}{2} , - \frac{5}{4}\right)$ graph{x^2-3x+1 [-10, 10, -5, 5]}[Ans]