Question

How do you write `f(x)=x^2-6x+14` in vertex form?

Answer 1

`y-5= (x-3)^2`

Explanation:

Answer 2

`y = (x - 3)^2 + 5`

Explanation:

General vertex form, if (xV) is the x- coordinate of vertex
`y = a(x - xV)^2 + y(xV)`
x-coordinate of vertex:
`xV = -b/(2a) = 6/2 = 3`
y-coordinate of vertex:
`y(xV= 3) = 9 - 18 + 14 = 5`
Vertex (3, 5)
Vertex form of y:
`y = (x - 3)^2 + 5`