Question

How do you write `f(x) = x^2 +8x + 10` into vertex form?

Answer 1

`f(x) = (x + 4)^2 - 6`

Explanation:

`f(x) = x^2 + 8x + 10`
x-coordinate of vertex:
`x = -b/(2a) = -8/2 = - 4`
y-coordinate of vertex:
`y(-4) = 16 - 32 + 10 = -6`
Vertex form:
`f(x) = (x + 4)^2 - 6`