# How do you write f(x) = x^2 +8x + 10 into vertex form?

Jul 4, 2016

$f \left(x\right) = {\left(x + 4\right)}^{2} - 6$

#### Explanation:

$f \left(x\right) = {x}^{2} + 8 x + 10$
x-coordinate of vertex:
$x = - \frac{b}{2 a} = - \frac{8}{2} = - 4$
y-coordinate of vertex:
$y \left(- 4\right) = 16 - 32 + 10 = - 6$
Vertex form:
$f \left(x\right) = {\left(x + 4\right)}^{2} - 6$