How do you write #f(x) = x² - 8x +11# in vertex form?
To go from Standard Form to Vertex Form, we need to complete the square. That means we need to find the constant that makes
To find that constant, we use this equation:
We now have the constant that completes the square, but we can't just add a value to an equation. We can either add
That's our vertex form, so now we're done. Good job!