# How do you write the complex number -2-3i in polar form?

Polar form of $- 2 - 3 i = \left(3.6056 , {236.31}^{\circ}\right)$
$z = a + i b = r \left(\cos \theta + i \sin \theta\right)$
$r = | \sqrt{{a}^{2} + {b}^{2}} | = \sqrt{- {2}^{2} + - {3}^{2}} = 3.6056$
$\theta = {\tan}^{-} 1 \left(\frac{b}{a}\right) = {\tan}^{-} 1 \left(- \frac{3}{-} 2\right) = {236.31}^{\circ} \text{ Point in III Quadrant}$