# How do you write the electron configuration of tin?

$S n :$ $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{10} 4 {p}^{6} 4 {d}^{10} 5 {s}^{2} 5 {p}^{2}$
For tin, $Z = 50$..........
And thus 50 electrons must be distributed according to the usual $\text{aufbau}$ scheme...........Tin lies in Group 14, and thus should have a similar electronic configuration to carbon. Can you demonstrate the similarity.