How do you write the equation in slope intercept form given #-5x + 7y = 1#?

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Answer 1 · 2017-02-07T04:56:04

#y = color(red)(5/7)x + color(blue)(1/7)#

The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

We need to solve for #y# as follows:

#color(red)(5x) - 5x + 7y = color(red)(5x) + 1#

#0 + 7y = 5x + 1#

#7y = 5x + 1#

#(7y)/color(red)(7) = (5x + 1)/color(red)(7)#

#(color(red)(cancel(color(black)(7)))y)/cancel(color(red)(7)) = (5x)/7 + 1/7#

#y = color(red)(5/7)x + color(blue)(1/7)#