How do you write the equation of a line that passes through the point (3, -6) and has a slope of 4?

1 Answer
May 20, 2017

Answer:

#y=4x-18#

Explanation:

#"the equation of a line in "color(blue)"point-slope form "# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represent the slope and # (x_1,y_1)" a point on the line"#

#"here " m=4" and " (x_1,y_1)=(3,-6)#

#y-(-6)=4(x-3)#

#rArry+6=4(x-3)larrcolor(red)" in point-slope form"#

#"distributing and simplifying gives another version"#

#y+6=4x-12#

#rArry=4x-12-6#

#rArry=4x-18larrcolor(red)" in slope-intercept form"#