How do you write the equation of each parabola in vertex form given vertex at (0,4) and passes through the point (-1,6)?

1 Answer
Feb 27, 2016

#y=2x^2+4#

Explanation:

#y=a(x-h)^2+k# => equation of the parabola in vertex form where:
(h, k) is the coordinates of the vertex.
So in this case we substitute the given coordinates in the formula:
#y=a(x-0)^2+4# => simplify:
#y=ax^2+4# => to solve for a we substitute the given coordinates:
#6=a*(-1)^2+4# => simplify:
#6=a+4# => solve for a
#6-4=a# => or:
#a=2# => substitute for a and the required equation is:
#y=2x^2+4#