# How do you write the equation of the line containing the point (-2,-1) parallel to y=-3/2x-1?

##### 1 Answer

May 7, 2016

#y=-3/2x-4#

#### Explanation:

Equation of the given line -

#y=-3/2x-1#

Slope of the line

#m_1=-3/2#

Parallel line's slope is

Hence, the slope of the parallel line is

#m_2=-3/2#

The parallel line is passing through the point

Find the equation of the line-

#y=mx+c#

#-1=-3/2 .(-2)+c#

#-1=6/2+c=3+c#

By trnspose, we get,

#3+c=-1#

#c=-1-3=-4#

Then the equation is-

#y=-3/2x-4#