# How do you write the equation of the line containing the point (-2,-1) parallel to y=-3/2x-1?

May 7, 2016

$y = - \frac{3}{2} x - 4$

#### Explanation:

Equation of the given line -

$y = - \frac{3}{2} x - 1$
Slope of the line
${m}_{1} = - \frac{3}{2}$

Parallel line's slope is ${m}_{1} = {m}_{2}$
Hence, the slope of the parallel line is

${m}_{2} = - \frac{3}{2}$

The parallel line is passing through the point $\left(- 2 , - 1\right)$

Find the equation of the line-

$y = m x + c$
$- 1 = - \frac{3}{2} . \left(- 2\right) + c$
$- 1 = \frac{6}{2} + c = 3 + c$

By trnspose, we get,

$3 + c = - 1$
$c = - 1 - 3 = - 4$
Then the equation is-
$y = - \frac{3}{2} x - 4$