Question

How do you write the noble-gas electron configuration for B?

Answer 1

The noble gas configuration is the same for all elements (`s^2p^6`)
or in the case of Helium only (`s^2` )

Explanation:

B for Boron does not achieve the noble gas configuration by adding electrons so it does not reach the configuration of the noble gas Neon `Ne_10` (`2s^2 2p^6`)

Boron achieves the noble gas configuration by losing electrons. So
`B_5^11` losing three electrons to achieve the noble gas configuration of `He_2^4` ( `1s^2`)

Answer 2

The noble gas electron configuration boron is `"[He]2s"^2 "2p"`.

Explanation:

Boron is element number 5 in the Periodic Table.

Thus, its electron configuration is `"1s"^2 "2s"^2 "2p"`.

The noble gas that comes before boron in the Periodic Table is helium.

Its electron configuration is `"1s"^2`.

Hence, the noble gas electron configuration of boron is `"[He]2s"^2 "2p"`.