# How do you write the noble-gas electron configuration for B?

Oct 1, 2016

The noble gas configuration is the same for all elements (${s}^{2} {p}^{6}$)
or in the case of Helium only (${s}^{2}$ )

#### Explanation:

B for Boron does not achieve the noble gas configuration by adding electrons so it does not reach the configuration of the noble gas Neon $N {e}_{10}$ ($2 {s}^{2} 2 {p}^{6}$)

Boron achieves the noble gas configuration by losing electrons. So
${B}_{5}^{11}$ losing three electrons to achieve the noble gas configuration of $H {e}_{2}^{4}$ ( $1 {s}^{2}$)

Oct 29, 2016

The noble gas electron configuration boron is $\text{[He]2s"^2 "2p}$.

#### Explanation:

Boron is element number 5 in the Periodic Table.

Thus, its electron configuration is $\text{1s"^2 "2s"^2 "2p}$.

The noble gas that comes before boron in the Periodic Table is helium.

Its electron configuration is ${\text{1s}}^{2}$.

Hence, the noble gas electron configuration of boron is $\text{[He]2s"^2 "2p}$.