# How do you write the noble-gas electron configuration for carbon?

$\left[H e\right] 2 {s}^{2} 2 {p}^{2}$.......
For carbon $Z = 6$, and if there are 6 positively charge nuclear particles, there must be 6 negatively charged extra-nuclear particles in the neutral atom.
$\left\{1 {s}^{2}\right\} 2 {s}^{2} 2 {p}^{2}$