# How do you write the point slope form of an equation for a lint that passes through (1,-4) with m=-8/3?

Apr 15, 2017

$y + 4 = - \frac{8}{3} \left(x - 1\right)$

#### Explanation:

The equation of a line in $\textcolor{b l u e}{\text{point-slope form}}$ is.

$\textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{y - {y}_{1} = m \left(x - {x}_{1}\right)} \textcolor{w h i t e}{\frac{2}{2}} |}}}$
where m represents the slope and $\left({x}_{1} , {y}_{1}\right) \text{ a point on the line}$

$\text{here " m=-8/3" and } \left({x}_{1} , {y}_{1}\right) = \left(1 , - 4\right)$

Substitute these values into the equation.

$y - \left(- 4\right) = - \frac{8}{3} \left(x - 1\right)$

$\Rightarrow y + 4 = - \frac{8}{3} \left(x - 1\right) \leftarrow \textcolor{red}{\text{ in point-slope form}}$