How do you write the quadratic function #y=-4x^2-2x-3# in vertex form?

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Answer 1 · 2017-04-05T15:37:05

#y=-4(x+1/4)^2-11/4#

#y=a(x-h)^2+k " vertex form"#

#"Where (h,k) is vertex coordinates."#

#y=-4x^2-2x-3#

#y=-4(x^2+x/2+3/4)#

#y=-4(x^2+x/2color(red)(+1/16-1/16)+3/4)#

#y=-4[(x^2+x/2+1/16)-1/16+3/4]#

#(x^2+x/2+1/16)=(x+1/4)^2#

#-1/16+3/4=(-1+12)/16=11/16#

#y=-4[(x+1/4)^2+11/16]#

#y=-4(x+1/4)^2-cancel(4)*11/cancel(16)#

#y=-4(x+1/4)^2-11/4#