Question

How do you write the quadratic function `y=x^2+14x+11` in vertex form?

Answer 1

The quadratic function in vertex form is `y=(x+7)^2 -38`

Explanation:

`y= x^2+14x+11 or y= (x+7)^2 -49+11 or y=(x+7)^2 -38`

Comparing with standard vertex form `y=a(x-h)^2+k`, where `(h,k)` is vertex. So vertex is at `(-7 , -38)`

The quadratic function in vertex form is `y=(x+7)^2 -38` graph{x^2+14x+11 [-160, 160, -80, 80]}[Ans]