# How do you write the quadratic function y=x^2+14x+11 in vertex form?

The quadratic function in vertex form is $y = {\left(x + 7\right)}^{2} - 38$
$y = {x}^{2} + 14 x + 11 \mathmr{and} y = {\left(x + 7\right)}^{2} - 49 + 11 \mathmr{and} y = {\left(x + 7\right)}^{2} - 38$
Comparing with standard vertex form $y = a {\left(x - h\right)}^{2} + k$, where $\left(h , k\right)$ is vertex. So vertex is at $\left(- 7 , - 38\right)$
The quadratic function in vertex form is $y = {\left(x + 7\right)}^{2} - 38$ graph{x^2+14x+11 [-160, 160, -80, 80]}[Ans]