# How do you write the quadratic in vertex and standard form given the vertex ( -1, 0) and passes through ( -4, -72)?

##### 1 Answer

May 21, 2015

The standard form is : y = ax^2 + bx + c. Find a, b, and c.

x of vertex:

y of vertex: f(-1) = 0 = a - b + c = a - 2a + c = 0 -> a = c

The parabola passes at point (-4, -72):

Standard form:

Check:

x of vertex: -b/2a = 16/-16 = -1. OK

y of vertex: f(-1) = -8 + 16 - 8 = 0 . OK