# How do you write the quadratic in vertex form given y=1/3x^2-16/3x+64/3 ?

May 24, 2015

$y = {x}^{2} / 3 - 16 \frac{x}{3} + \frac{64}{3} = \frac{1}{3} \left({x}^{2} - 16 x + 64\right) = \frac{1}{3} {\left(x - 8\right)}^{2}$