Question

How do you write the quadratic in vertex form given `y= x^2 - 12x + 20`?

Answer 1

`(-b/2a) = -12/2 = 6`

`f(-b/2a) = f(6) = 36 - 72 + 20 = -16`

Factored form:`f(x) = (x - 6)^2 - 16`

Check:
`Develop f(x) = (x^2 - 12x + 36 - 16 = x^2 - 12x + 20`. Correct