How do you write the quadratic in vertex form given $y=x^2-5$ ?

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Answer 1 · 2015-04-29T18:46:22

The vertex form of a quadratic function is given by
$y = a(x - h)^2 + k$ , where $(h, k)$ is the vertex of the parabola.

We can write the given equation as $color(green)(y = 1*(x - 0)^2 + (-5)$ where $a = 1; h = 0; k = -5$

The vertex of the Parabola is ${0 , -5}$

How do you write the quadratic in vertex form given y=x^2-5y=x^2-5?