# How do you write the quadratic in vertex form given y=x^2-5?

$y = a {\left(x - h\right)}^{2} + k$, where $\left(h , k\right)$ is the vertex of the parabola.
We can write the given equation as  color(green)(y = 1*(x - 0)^2 + (-5) where  a = 1; h = 0; k = -5
The vertex of the Parabola is$\left\{0 , - 5\right\}$