# How do you write the quadratic y=2x^2 +11x-6 in vertex form?

$y = k {\left(x - a\right)}^{2} + b$
where the vertex is $\left(a , b\right)$
$y = 2 {x}^{2} + 11 x - 6$
$y = 2 \left({x}^{2} + \frac{11}{2} x + {\left(\frac{11}{4}\right)}^{2}\right) - 2 {\left(\frac{11}{4}\right)}^{2} - 6$
$y = 2 {\left(x - \left(- \frac{11}{4}\right)\right)}^{2} + \left(- \frac{169}{8}\right)$