Question

How do you write the quadratic `y=2x^2 +11x-6` in vertex form?

Answer 1

The vertex form of a parabola is
`y = k(x-a)^2 +b`
where the vertex is `(a,b)`

`y=2x^2+11x-6`

`y= 2(x^2+11/2x+(11/4)^2) -2(11/4)^2 -6`

`y = 2(x-(-11/4))^2 +(-169/8)`