# How do you write the slope intercept form of the line 11x-8y=-48?

Feb 12, 2017

$y = \frac{11}{8} x + 6$

#### Explanation:

The equation of a line in $\textcolor{b l u e}{\text{slope-intercept form}}$ is.

$\textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{y = m x + b} \textcolor{w h i t e}{\frac{2}{2}} |}}}$
where m represents the slope and b, the y-intercept.

$\text{Rearrange " 11x-8y=-48" into this form}$

subtract 11x from both sides of the equation.

$\cancel{11 x} \cancel{- 11 x} - 8 y = - 11 x - 48$

$\Rightarrow - 8 y = - 11 x - 48$

divide all terms on both sides by - 8

$\frac{\cancel{- 8} y}{\cancel{- 8}} = \frac{- 11}{- 8} x - \frac{48}{- 8}$

$\Rightarrow y = \frac{11}{8} x + 6 \leftarrow \textcolor{red}{\text{ in slope-intercept form}}$