# How do you write the slope intercept form of the line #11x-8y=-48#?

##### 1 Answer

Feb 12, 2017

#### Explanation:

The equation of a line in

#color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#

where m represents the slope and b, the y-intercept.

#"Rearrange " 11x-8y=-48" into this form"# subtract 11x from both sides of the equation.

#cancel(11x)cancel(-11x)-8y=-11x-48#

#rArr-8y=-11x-48# divide all terms on both sides by - 8

#(cancel(-8) y)/cancel(-8)=(-11)/(-8)x-48/(-8)#

#rArry=11/8x+6larrcolor(red)" in slope-intercept form"#