# How do you write the standard form of a line given (1, 5), m = -3?

Aug 18, 2017

$y = - 3 x + 8$

$3 x + y = 8 \text{ } \leftarrow$standard form

#### Explanation:

Use the point-slope formula: $y - {y}_{1} = m \left(x - {x}_{1}\right)$

We have $\left(1 , 5\right) = \left({x}_{1} , {y}_{1}\right) \mathmr{and} m = - 3$

$y - 5 = - 3 \left(x - 1\right)$

$y - 5 = - 3 x + 3$

$y = - 3 x + 3 + 5$

$y = - 3 x + 8 \text{ } \leftarrow y$-intercept/gradient form.

$3 x + y = 8 \text{ } \leftarrow$standard form

$3 x + y - 8 = 0 \text{ } \leftarrow$ general form

I hope that helps!