How do you write the trigonometric form of #1+3i#?
1 Answer
Apr 7, 2018
Explanation:
#"to convert to "color(blue)"trigonometric form"#
#"that is "x+yitor(costheta+isintheta)" using"#
#•color(white)(x)r=sqrt(x^2+y^2)#
#•color(white)(x)theta=tan^-1(y/x);-pi < theta <=pi#
#"here "x=1" and "y=3#
#rArrr=sqrt(1^2+3^2)=sqrt10#
#theta=tan^-1(3)=1.249" radians"#
#rArr1+3itosqrt10(cos1.249+isin1.249)#
