How do you write the vector equation that passes through point (1,0) and parallel to <-2,-4>?

1 Answer
Dec 8, 2016

Answer:

#vecr=(lambda+1)veci-2vecj#

Explanation:

the vector eqn. of a line is given by

#vecr=veca+lambdavecd#

where

#vecr" "#is the general vector point on the line

#veca" "#is a known vector point on the line

#vecd" "#is the direction of the line

#lamda" "# is a scalar

in this case #veca=veci#

#vecd=2veci-4vecj #or #veci-2vecj" "#in its simplest form

#:.vecr=veci+lambda(veci-2vecj)=(lambda+1)veci-2vecj#